$$(\frac{4}{9})^{-1/2}+(\frac{1}{16})^{3/4}$$
primero lo primero: potencia negativa invierte la base
potencia fraccionaria: el denominador es raiz
entonces:
$$(\frac{4}{9})^{-1/2}=\sqrt {\frac{9}{4}}=\frac{3}{2}$$
$$(\frac{1}{16})^{3/4}= (\sqrt[4]{\frac{1}{16}})^3=(\frac{1}{2})^3=\frac{1}{8}$$
finalmente:
$$(\frac{4}{9})^{-1/2}+(\frac{1}{16})^{3/4}=\frac{3}{2}+\frac{1}{8}=\frac{4.3+1}{8}=\frac{13}{8}$$
Firma
"if people do not believe that mathematics is simple, it is only because they do not realize how complicate life is"