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UBA - CienciaS :: Ver Tema - [Resuelto] Práctica 5 - ej 2
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[Resuelto] Práctica 5 - ej 2
http://ubacs.com.ar/ubacs/viewtopic.php?f=161&t=1170
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Autor:  bel [ 06 Jun 2009, 01:25 ]
Asunto:  [Resuelto] Práctica 5 - ej 2

Un disco de Faraday, consistente en un disco de cobre de radio a cuyo eje es paralelo a un campo magnético uniforme B, rota con una velocidad ángular . Calcular la fem que aparece entre los puntos el centro del disco y un punto en el borde de la circunferencia.


Considero primero un sistema de referencia fijo al a Tierra, desde el cual veo rotar al disco y las partículas tienen una velocidad .
La fuerza de Lorentz indica que sobre una partícula de carga q, (supongamos un electrón) actúa una fuerza electromagnética . Pero el campo eléctrico es 0 (la carga neta del disco es 0).
Entonces, sobre cada carga de carga q actuará una fuerza magnética si . Ahora, si considero un sistema de referencia fijo al disco, las cargas están quietas, es decir que sobre ellas no actúa ninguna fuerza magnética, de modo que la fuerza de Lorentz indica que . Como la fuerza de origen electromagnético que actúa sobre la partícula ha de ser la misma en cada sistema de referencia (no se ve afectada por transformaciones galileanas), deducimos que , entonces:



y.. chanan.

Bueno, espero haberlo explicado bien (aclaré cosas que me aclararon hoy en clase). Cualquier cosa que vean que no les convenza no duden en decirme. Besos!

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