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UBA - CienciaS • Ver Tema - [No resuelto]
UBACS Q&A Foro WikiCS
Fecha actual 19 Abr 2024, 01:07

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Autor Mensaje
 Asunto: [No resuelto]
NotaPublicado: 14 Dic 2008, 16:34 
Ayudante de Primera

Registrado: 01 Ago 2008, 00:26
Mensajes: 104
Gente, ¿alguno sabe la demostración de este teorema?:
TEOREMA

Si el Número Irracional , es un Cero ( Raíz ) de un Polinomio que tiene Coeficientes Racionales, entonces el Número Irracional también es un Cero ( Raíz )del Polinomio.

Desde ya muchísimas gracias.:)


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 Asunto: Re: [No resuelto]
NotaPublicado: 14 Dic 2008, 16:58 
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Registrado: 17 May 2008, 23:04
Mensajes: 812
Te tiro los pasos para demostrarlo:
a)probá que el conjunto no cuadrado perfecto, positivo, n no nulo y m,n ,d todos enteros, es un cuerpo, o sea, tiene inverso multiplicativo, la suma de dos elementos del conjunto es un elemento del conjunto, el producto también, asociatividad, distributiva, conmutatividad, etc...
b)definí una aplicación que sea como el conjugado de los números complejos, o sea,
c)probá que tiene las ''mismas'' propiedades(distributiva con el producto y la suma) que la conjugación de los números complejos
d)copiá la demostración de los números complejos, que si un complejo es raíz de un polinomio real, su conjugado también(o sea, para el polinomio racional, si tenés una raíz de esta forma, aplicá a toda esa expresión. El 0 no te lo va a cambiar ni los coeficientes, pero si esa raíz, para obtener esta ''conjugada'')
Fijate si con estos pasos, sale.
Saludos.



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